document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=954871>Question 954871</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I can not figure out the answer to this word problem, one number is 3 less than 6 times the second number their sum is 46. find the numbers, could you please help me.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #583234 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=583234\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x and y are the numbers<BR>\n" );
document.write( "x=6y-3<BR>\n" );
document.write( "x+y=46 Substitute for x.<BR>\n" );
document.write( "6y-3+y=46<BR>\n" );
document.write( "7y=49<BR>\n" );
document.write( "y=7 ANSWER 1: One of the numbers is 7.<BR>\n" );
document.write( "x+y=46<BR>\n" );
document.write( "x=46-y<BR>\n" );
document.write( "x=46-7=39 ANSWER 2: The other number is 39.<BR>\n" );
document.write( "CHECK:<BR>\n" );
document.write( "x=6y-3<BR>\n" );
document.write( "39=6(7)-3<BR>\n" );
document.write( "39=42-3<BR>\n" );
document.write( "39=39 </SPAN>\n" );
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