document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=954800>Question 954800</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Maya's Coffee Shop makes a blend that is a mixture of two types of coffee. Type A coffee costs Maya <BR>\n" );
document.write( "$4.35 per pound, and type B coffee costs $5.70 per pound. This month, Maya made 167 pounds of the blend, for a total cost of $846.60. How many pounds of type B coffee did she use? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #583188 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=583188\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A+B=167lbs<BR>\n" );
document.write( "A=167lbs-B<BR>\n" );
document.write( "$4.35A+$5.70B=$846.60 Substitute for A<BR>\n" );
document.write( "$4.35(167lbs-B)+$5.70B=$846.60<BR>\n" );
document.write( "$726.45-$4.35B+$5.70B=$846.60 Subtract $726.45 from each side.<BR>\n" );
document.write( "$1.35B=$120.15 Divide each side by $1.35.<BR>\n" );
document.write( "B=89 lbs ANSWER: The mix contained 89 pounds of Type B coffee.<BR>\n" );
document.write( "CHECK:<BR>\n" );
document.write( "167lbs-89lbs=78 lbs She used 78 pounds of Type A coffee.<BR>\n" );
document.write( "$4.35A+$5.70B=$846.60<BR>\n" );
document.write( "$4.35(78)+$5.70(89)=$846.60<BR>\n" );
document.write( "$339.30+$507.30=$846.60<BR>\n" );
document.write( "$846.60=$846.60 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );