document.write( "Question 954779: You invested 5000 between two accounts paying 3% and 8% annual interest, respectively. If the total interest earned for the year was $250, how much was invested at each rate? \n" ); document.write( "
Algebra.Com's Answer #583172 by macston(5194)![]() ![]() You can put this solution on YOUR website! T=amount invested at 3%; E=amount invested at 8% \n" ); document.write( "T+E=5000 \n" ); document.write( "T=5000-E \n" ); document.write( "0.03T+0.08E=$250 Substitute for T. \n" ); document.write( "0.03(5000-E)+0.08E=$250 \n" ); document.write( "150-0.03E+0.08E=$250 Subtract 150 from each side. \n" ); document.write( "0.05E=$100 Divide each side by 0.05 \n" ); document.write( "E=$2000 ANSWER 1: $2000 was invested at 8%. \n" ); document.write( "T=5000-E=5000-2000=3000 ANSWER 2: $3000 was invested at 3%. \n" ); document.write( "CHECK: \n" ); document.write( "0.03T+0.08E=$250 \n" ); document.write( "0.03($3000)+0.08($2000)=$250 \n" ); document.write( "$90+$160=$250 \n" ); document.write( "$250=$250 \n" ); document.write( " |