document.write( "Question 81399: The perimeter of a rectangle is 44ft. The length of the rectangle is 2ft less than three times the width. Find the length of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #58317 by iheartcrmnljstce(1)\"\" \"About 
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The perimeter is 44 ft. \r
\n" ); document.write( "\n" ); document.write( "Perimeter is the two lengths and two widths added together. \r
\n" ); document.write( "\n" ); document.write( "Let each width be x. \r
\n" ); document.write( "\n" ); document.write( "Each length is 2ft less than 3 times the width...\r
\n" ); document.write( "\n" ); document.write( "...2ft less than ...means you are subtracting from the 3 times the width\r
\n" ); document.write( "\n" ); document.write( "3 times the width equals 3x\r
\n" ); document.write( "\n" ); document.write( "then you subtract 2ft...\r
\n" ); document.write( "\n" ); document.write( "Each length is 3x - 2 \r
\n" ); document.write( "\n" ); document.write( "So you must add two widths and two lengths to equal the perimeter...\r
\n" ); document.write( "\n" ); document.write( "x+x+(3x-2)+(3x-2)=44\r
\n" ); document.write( "\n" ); document.write( "add similiar variables together...\r
\n" ); document.write( "\n" ); document.write( "x+x+3x+3x=8x\r
\n" ); document.write( "\n" ); document.write( "-2-2= -4\r
\n" ); document.write( "\n" ); document.write( "which equals... 8x-4=44
\n" ); document.write( " +4 +4
\n" ); document.write( " 8x=48
\n" ); document.write( "divide each side by 8
\n" ); document.write( " x=6 \r
\n" ); document.write( "\n" ); document.write( "then you need to plug in x to both the widths and lengths...\r
\n" ); document.write( "\n" ); document.write( " each width is 6\r
\n" ); document.write( "\n" ); document.write( " each length is (3(6)-2) --->18-2=16
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\n" ); document.write( "check answer by adding them together... 6+6=12, 16+16=32... 12+32=44\r
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\n" ); document.write( "\n" ); document.write( "The answer is each length is 16.
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