document.write( "Question 954708: Last year, Trey deposited $2000 into an account that paid 2% interest per year and $3000 into an account that paid 6% interest per year. No withdrawals were made from the accounts.
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document.write( "Answer the questions below. Do not do any rounding.\r
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document.write( "(a) What was the total interest earned at the end of 1 year?
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document.write( "$________________
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document.write( "(b) What was the percent interest for the total deposited?
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document.write( "__________%
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Algebra.Com's Answer #583156 by macston(5194)![]() ![]() You can put this solution on YOUR website! (0.02)($2000)+(0.06)($3000)=$40+$180=$220 \n" ); document.write( "(a)ANSWER 1: Total interest earned was $220. \n" ); document.write( "($220)/($5000)(100%)=4.4% \n" ); document.write( "(b)ANSWER 2:The overall percent interest for the amount deposited was 4.4%. \n" ); document.write( " |