document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=81408>Question 81408</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A skeleton contains one hundredth of its original amount of its original amount of carbon-14. If carbon-14 has a half-life of 5750 years, to the nearest 1000 years, how old is the skeleton? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #58312 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=58312\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A skeleton contains one hundredth of its original amount of its original amount of carbon-14. If carbon-14 has a half-life of 5750 years, to the nearest 1000 years, how old is the skeleton?<BR>\n" );
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document.write( "A(t) = A(o)(1/2)^(t/5750)<BR>\n" );
document.write( "0.01A(o) = A(o)(1/2)^(t/5750)<BR>\n" );
document.write( "0.01 = 0.5^(t/5750)<BR>\n" );
document.write( "Take the log of both sides to get:<BR>\n" );
document.write( "log 0.01 = (t/5750)*log0.5<BR>\n" );
document.write( "t/5750 = log0.01/log0.5 =6.64385619...<BR>\n" );
document.write( "t = 38202 yrs<BR>\n" );
document.write( "==============<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );