document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=954689>Question 954689</A>: <I><SPAN STYLE=\"word-break: break-all;\"> THE LATERAL AREA OF THE FRUSTUM IS EQUIVALENT TO\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #583093 by </B><A HREF=/tutors/aboutme.mpl?userid=MathLover1><B>MathLover1(20850)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=MathLover1><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=MathLover1><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=583093\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The frustum is that portion of a solid which lies <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=between ALIGN=MIDDLE  ALT=\"between\"   DISABLED_style= \"max-width:90%; height:auto;\" > two parallel planes cutting the solid and has a top base radius <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=r%5B1%5D ALIGN=MIDDLE  ALT=\"r%5B1%5D\"   DISABLED_style= \"max-width:90%; height:auto;\" >, bottom base radius <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=r%5B2%5D ALIGN=MIDDLE  ALT=\"r%5B2%5D\"   DISABLED_style= \"max-width:90%; height:auto;\" >, height <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=h ALIGN=MIDDLE  ALT=\"h\"   DISABLED_style= \"max-width:90%; height:auto;\" >, and slant height <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=s ALIGN=MIDDLE  ALT=\"s\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
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document.write( "slant height (<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=s ALIGN=MIDDLE  ALT=\"s\"   DISABLED_style= \"max-width:90%; height:auto;\" >) could be found using a formula:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=s=sqrt%28%28r%5B1%5D-r%5B2%5D%29%29%5E2%2Bh%5E2%29 ALIGN=MIDDLE  ALT=\"s=sqrt%28%28r%5B1%5D-r%5B2%5D%29%29%5E2%2Bh%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "The LATERAL surface area, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=not ALIGN=MIDDLE  ALT=\"not\"   DISABLED_style= \"max-width:90%; height:auto;\" > including the top and bottom circles, is\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=LA=pi%2A%28r%5B1%5D%2Br%5B2%5D%29s ALIGN=MIDDLE  ALT=\"LA=pi%2A%28r%5B1%5D%2Br%5B2%5D%29s\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=LA=pi%2A%28r%5B1%5D%2Br%5B2%5D%29sqrt%28%28r%5B1%5D-r%5B2%5D%29%29%5E2%2Bh%5E2%29 ALIGN=MIDDLE  ALT=\"LA=pi%2A%28r%5B1%5D%2Br%5B2%5D%29sqrt%28%28r%5B1%5D-r%5B2%5D%29%29%5E2%2Bh%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "and the TOTAL surface area will be greater for a top base and bottom base area which are <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=r%5B1%5D%5E2%2Api ALIGN=MIDDLE  ALT=\"r%5B1%5D%5E2%2Api\"   DISABLED_style= \"max-width:90%; height:auto;\" > and <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=r%5B2%5D%5E2%2Api ALIGN=MIDDLE  ALT=\"r%5B2%5D%5E2%2Api\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=TA=pi%2A%28%28r%5B1%5D%2Br%5B2%5D%29sqrt%28%28r%5B1%5D-r%5B2%5D%29%29%5E2%2Bh%5E2%29%2Br%5B1%5D%5E2%2Api%2Br%5B2%5D%5E2%2Api ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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