document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=954662>Question 954662</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the length of a rectangle is 5cm less than twice its width . if the length is decreased by 7cm and the width by 3 cm , the perimeter will be 96cm. find the dimensions of the original rectangle .<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #583082 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=583082\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> W=width; L=length=2W-5cm; P=perimeter=2(L+W)=116cm<BR>\n" );
document.write( "P=2(L+W)<BR>\n" );
document.write( "116cm=2(L+W) Divide each side by 2.<BR>\n" );
document.write( "58cm=L+W Substitute for L.<BR>\n" );
document.write( "58cm=2W-5cm+W Add 5cm to each side.<BR>\n" );
document.write( "63cm=3W Divide each side by 3.<BR>\n" );
document.write( "21cm=W ANSWER 1:The width is 21 cm.<BR>\n" );
document.write( "L=2W-5cm<BR>\n" );
document.write( "L=2(21cm)-5cm=42cm-5cm=37cm ANSWER 2: The length is 37 cm.<BR>\n" );
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