document.write( "Question 954560: The half-life of radium is 1600 years. If 1000g are initially present, how much will remain after 3200 years? How long will it take to decay to 50g? \n" ); document.write( "
Algebra.Com's Answer #583069 by josgarithmetic(39620)\"\" \"About 
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The first question is easily answered with no fancy calculations. 3200 years is TWO half-lives. 250 grams remain. Continuing in half-lives, you can come near the number of years to reach 50 grams, but a computation using the decay model might be better.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"y=I%2Ae%5E%28-kt%29\"
\n" ); document.write( "\"ln%28y%29=ln%28I%29-kt\"
\n" ); document.write( "\"-kt=ln%28y%29-ln%28I%29\"
\n" ); document.write( "\"k=%28ln%28I%29-ln%28y%29%29%2Ft\"
\n" ); document.write( "\"k=ln%282%29%2F1600\"
\n" ); document.write( "\"k=4.33%2A10%5E%28-4%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The decay formula will give \"t=ln%28I%2Fy%29%2Fk\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"highlight%28t%5B50g%5D=ln%281000%2F50%29%2F%280.000433%29%29\"
\n" ); document.write( "compute that, for years.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "6900 years
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