document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=954511>Question 954511</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have 15 kilograms of raw material (concrete) and need to add 7.5% water to it, how much is 7.5% of water in liters for 15 kilograms of material? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #583066 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=583066\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 0.075(15kg)=1.125kg<BR>\n" );
document.write( "1.125kg(1 liter water/1kg water)=1.125 liters<BR>\n" );
document.write( "ANSWER: 7.5% of 15 kg would be 1.125 kg or 1.125 liters water.<BR>\n" );
document.write( "Pure water weighs 1.000028 kg/liter so 1kg/liter is close enough for concrete.<BR>\n" );
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