document.write( "Question 81415: Can you help me solve please?\r
\n" );
document.write( "\n" );
document.write( "x/x-3+2=3/x-3 I don't see a solution but i am not sure \n" );
document.write( "
Algebra.Com's Answer #58306 by stanbon(75887) ![]() You can put this solution on YOUR website! Can you help me solve please? \n" ); document.write( "x/(x-3) + 2 = 3/(x-3) \n" ); document.write( "Multiply thru by (x-3) to get: \n" ); document.write( "x + 2(x-3) = 3 \n" ); document.write( "x + 2x -6 = 3 \n" ); document.write( "3x=9 \n" ); document.write( "x=3 \n" ); document.write( "But x cannot be 3 because the original problem has x-3 in the denominator \n" ); document.write( "and letting x=3 would cause the denoinator to be zero. \n" ); document.write( "So, no solution for your problem. \n" ); document.write( "=============== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |