document.write( "Question 81415: Can you help me solve please?\r
\n" ); document.write( "\n" ); document.write( "x/x-3+2=3/x-3 I don't see a solution but i am not sure
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Algebra.Com's Answer #58306 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Can you help me solve please?
\n" ); document.write( "x/(x-3) + 2 = 3/(x-3)
\n" ); document.write( "Multiply thru by (x-3) to get:
\n" ); document.write( "x + 2(x-3) = 3
\n" ); document.write( "x + 2x -6 = 3
\n" ); document.write( "3x=9
\n" ); document.write( "x=3
\n" ); document.write( "But x cannot be 3 because the original problem has x-3 in the denominator
\n" ); document.write( "and letting x=3 would cause the denoinator to be zero.
\n" ); document.write( "So, no solution for your problem.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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