document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=954598>Question 954598</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of the ages of a father and son is 56. Four years ago the father was 3 times as old as the son. Find the present age of each. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #583052 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=583052\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> F=father; S=son<BR>\n" );
document.write( "F+S=56yrs<BR>\n" );
document.write( "F=56yrs-S<BR>\n" );
document.write( "F-4yrs=3(S-4yrs) Substitute for F.<BR>\n" );
document.write( "56yrs-S-4yrs=3S-12 yrs Add S+12yrs to each side.<BR>\n" );
document.write( "64yrs=4S Divide each side by 4.<BR>\n" );
document.write( "16yrs=S ANSWER 1: The son is 16 years old.<BR>\n" );
document.write( "F=56yrs-S=56yrs-16yrs=40yrs ANSWER 2: The father is 40 years old.<BR>\n" );
document.write( "CHECK:<BR>\n" );
document.write( "F-4yrs=3(S-4yrs)<BR>\n" );
document.write( "40yrs-4yrs=3(16yrs-4yrs)<BR>\n" );
document.write( "36yrs=36yrs </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );