document.write( "Question 954402: A certain number of two digits is three times the sum of the digit. If 45 is added to it the digits are reversed.Find the number. \n" ); document.write( "
Algebra.Com's Answer #583050 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! let a = the 10's digit \n" ); document.write( "let b = the units \n" ); document.write( "then \n" ); document.write( "10a + b = the number \n" ); document.write( ": \n" ); document.write( "A certain number of two digits is three times the sum of the digit. \n" ); document.write( "10a + b = 3(a + b) \n" ); document.write( "10a + b = 3a + 3b \n" ); document.write( "10a - 3a = 3b - b \n" ); document.write( "7a = 2b \n" ); document.write( " If 45 is added to it the digits are reversed.Find the number. \n" ); document.write( "10a + b + 45 = 10b + a \n" ); document.write( "10a - a + 45 = 10b - b \n" ); document.write( "9a + 45 = 9b \n" ); document.write( "simplify, divide by 9 \n" ); document.write( "a + 5 = b \n" ); document.write( "a = b - 5 \n" ); document.write( "Back to our 1st equation, replace a with (b-5) \n" ); document.write( "7(b-5) = 2b \n" ); document.write( "7b - 35 = 2b \n" ); document.write( "7b - 2b = 35 \n" ); document.write( "5b = 35 \n" ); document.write( "b = 7 \n" ); document.write( "find a using the equation; a = b - 5 \n" ); document.write( "a = 7 - 5 \n" ); document.write( " a = 2 \n" ); document.write( "Our number: 27 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Confirm this in the statement: \n" ); document.write( "\"If 45 is added to it the digits are reversed\" \n" ); document.write( "27 + 45 = 72 \n" ); document.write( " |