document.write( "Question 81412: a passenger train can travel 325 mi in the same time a freight train takes to travel 200 mi. If the speed of the passanger train is 25 mi/phr faster than the speed fo the freight train, find the speed of each. \n" ); document.write( "
Algebra.Com's Answer #58305 by stanbon(75887)\"\" \"About 
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a passenger train can travel 325 mi in the same time a freight train takes to travel 200 mi. If the speed of the passanger train is 25 mi/phr faster than the speed fo the freight train, find the speed of each.
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\n" ); document.write( "Passenger train DATA:
\n" ); document.write( "distance=25 mi ; rate = x mph ; time = d/r = 325/x hrs
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\n" ); document.write( "Freight train DATA:
\n" ); document.write( "distance = 200 m ; rate = x-25 mph ; time = d/r = 200/(x-25) hr
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\n" ); document.write( "EQUATION:
\n" ); document.write( "time = time
\n" ); document.write( "325/x = 200/(x-25
\n" ); document.write( "Crsoo- multiply to get:
\n" ); document.write( "325(x-25) = 200x
\n" ); document.write( "325x-8125 = 200x
\n" ); document.write( "125x = 8125
\n" ); document.write( "x = 65 mph ( speed of passenger train)
\n" ); document.write( "x-25 = 40mph(speed of freight train)\r
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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