document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=954605>Question 954605</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how would you solve log 4 + log 2 - log 5? would you multiply log 4 & 2 and then use that answer to subtract log 5? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #583047 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=583047\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> how would you solve log 4 + log 2 - log 5? would you multiply log 4 & 2 and then use that answer to subtract log 5?<BR>\n" );
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document.write( "Logs are exponents.<BR>\n" );
document.write( "You add them to accomplish multiplication.<BR>\n" );
document.write( "You subtract them to accomplish division<BR>\n" );
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document.write( "Your Problem<BR>\n" );
document.write( "log(4) + log(2)- log(5) = log[4*2/5] = log(8/5)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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