document.write( "Question 954600: Please help me in this question!! \r
\n" ); document.write( "\n" ); document.write( "The perimeter of a rectangle is 54 centimeters, and it's area is 140 square centimeters. Find the dimensions of the rectangle.
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Algebra.Com's Answer #583046 by macston(5194)\"\" \"About 
You can put this solution on YOUR website!
P=2(L+W)
\n" ); document.write( "54cm=2(L+W)
\n" ); document.write( "27cm=L+W
\n" ); document.write( "27cm-W=L
\n" ); document.write( "A=L*W
\n" ); document.write( "\"140cm%5E2=L%2AW\" Substitute for L.
\n" ); document.write( "\"140cm%5E2=%2827cm-W%29W\"
\n" ); document.write( "\"140cm%5E2=27Wcm-W%5E2\"
\n" ); document.write( "\"W%5E2-27W%2B140=0\"\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"aW%5E2%2BbW%2Bc=0\" (in our case \"1W%5E2%2B-27W%2B140+=+0\") has the following solutons:
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\n" ); document.write( " \"W%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%28-27%29%5E2-4%2A1%2A140=169\".
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\n" ); document.write( " Discriminant d=169 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28--27%2B-sqrt%28+169+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"W%5B1%5D+=+%28-%28-27%29%2Bsqrt%28+169+%29%29%2F2%5C1+=+20\"
\n" ); document.write( " \"W%5B2%5D+=+%28-%28-27%29-sqrt%28+169+%29%29%2F2%5C1+=+7\"
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\n" ); document.write( " Quadratic expression \"1W%5E2%2B-27W%2B140\" can be factored:
\n" ); document.write( " \"1W%5E2%2B-27W%2B140+=+1%28W-20%29%2A%28W-7%29\"
\n" ); document.write( " Again, the answer is: 20, 7.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B-27%2Ax%2B140+%29\"

\n" ); document.write( "\n" ); document.write( "W=7cm
\n" ); document.write( "ANSWER:The width is 7cm.
\n" ); document.write( "L=27cm-W=20 cm ANSWER 2: The length is 20 cm.
\n" ); document.write( "CHECK:
\n" ); document.write( "A=L*W
\n" ); document.write( "\"140cm%5E2=20cm%2A7cm\"
\n" ); document.write( "\"140cm%5E2=140cm%5E2\"
\n" ); document.write( ".
\n" ); document.write( "P=2(L+W)
\n" ); document.write( "54cm=2(20cm+7cm)
\n" ); document.write( "54cm=2(27cm)
\n" ); document.write( "54cm=54cm
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