document.write( "Question 81410: the length of a rectangular playing field is is 5ft less than twice its width.If the perimeter of the playing field is 230ft, find the length and width of the field. \n" ); document.write( "
Algebra.Com's Answer #58304 by tutorcecilia(2152)\"\" \"About 
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Use the formula for the perimeter of a rectangle
\n" ); document.write( "P=2(Length+width)
\n" ); document.write( "P=230
\n" ); document.write( "Length=2w-5
\n" ); document.write( "Width=w
\n" ); document.write( ".
\n" ); document.write( "P=2(l+w) [plug-in the values]
\n" ); document.write( "230=2[(2w-5)+w] [solve for w]
\n" ); document.write( "230=2(3w-5)
\n" ); document.write( "230/2=2(3w-5)/2
\n" ); document.write( "115=3w-5
\n" ); document.write( "115+5=3w-5+5
\n" ); document.write( "120=3w
\n" ); document.write( "120/3=3w/3
\n" ); document.write( "40=w
\n" ); document.write( ".
\n" ); document.write( "So, if width =40, than the length is:
\n" ); document.write( "Length=2w-5=2(40)-5=80-5=75
\n" ); document.write( ".
\n" ); document.write( "Check by plugging all values back into the original formula and solve:
\n" ); document.write( "P=2(length + width)
\n" ); document.write( "230=2(75+40)
\n" ); document.write( "230=2(115)
\n" ); document.write( "230=230 [checks out] \n" ); document.write( "
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