document.write( "Question 954565: Six times ashleys age plus two times sydney's age equals 38. sydney's age is also three more than five times ashley's age/ how old is sydney? \n" ); document.write( "
Algebra.Com's Answer #583013 by aYummyNoodle(10)![]() ![]() ![]() You can put this solution on YOUR website! let x = Ashley's age. \n" ); document.write( "let y = Sydney's age. \n" ); document.write( "We can put the words into equations. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "There are many different ways of solving systems of linear equations which are graphing, substitution, and elimination. For this system I will use substitution and elimination. \n" ); document.write( "SUBSTITUTION: \n" ); document.write( "In the second equation, y is already isolated so we can just plug it in to the first equation: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Now that we know that \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "After finding out that \n" ); document.write( "(2,13) or: \n" ); document.write( "Ashley is 2 years old and Sydney is 13 years old. \n" ); document.write( "ELIMINATION: \n" ); document.write( "In elimination, we need to line the variables and coefficients up, so \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Multiply the second equation by 2 to get: \n" ); document.write( " \n" ); document.write( "By subtracting one equation from another, we can eliminate the y's and get: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "So Ashley is 2 years old. \n" ); document.write( "Plugging x back into the second equation, we get: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "So Sydney is 13 years old. \n" ); document.write( "Once again, Ashley is 2 years old and Sydney is 13 years old. \n" ); document.write( " |