document.write( "Question 954558: The perimeter of a rectangle is 30 inches. If its length is three times its width, find the dimensions \n" ); document.write( "
Algebra.Com's Answer #583008 by aYummyNoodle(10)\"\" \"About 
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We can assign the variable \"x\" and \"y\" to the length and width of the rectangle. In this case, I will assign \"x\" to the length and \"y\" to the width of the rectangle. As the length is three times its width, the equation would be:
\n" ); document.write( "\"x=3y\".
\n" ); document.write( "Finding the perimeter of a rectangle is always the sum of two times the length and two times the width. \"P\" stands for perimeter in this equation. That is:
\n" ); document.write( "\"P=2x%2B2y\".
\n" ); document.write( "In the first equation, we already have \"x\" isolated, we can plug it in to the second equation. We know that the perimeter is 30, so we can also plug that in for \"P\".
\n" ); document.write( "\"30=2%283y%29%2B2y\".
\n" ); document.write( "Simplifying us would give us
\n" ); document.write( "\"30=6y%2B2y\"
\n" ); document.write( "\"30=8y\".
\n" ); document.write( "\"y=3.75\"
\n" ); document.write( "So now we know that the width of the rectangle is 3.75.
\n" ); document.write( "We can now plug this back in to the original equation to get:
\n" ); document.write( "\"x=3%283.75%29\"
\n" ); document.write( "\"x=11.25\".
\n" ); document.write( "So the answer is Length=11.25 and Width=3.75.
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