document.write( "Question 1768: A rectangular yard is surrounded by a fence that is 4 feet longer than it is wide. If the perimeter of the fence is 424 feet, what are the dimensions of the yard it encloses? \n" ); document.write( "
Algebra.Com's Answer #583 by longjonsilver(2297)\"\" \"About 
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let one length of the yard be x. The other is then (x+4), seeing as how it is 4 feet longer.\r
\n" ); document.write( "\n" ); document.write( "the perimeter is then just the addition of all 4 lengths and that adds up to 424, so:\r
\n" ); document.write( "\n" ); document.write( "\"x+%2B+%28x%2B4%29+%2B+x+%2B+%28x%2B4%29+=+424\"
\n" ); document.write( "\"4x+%2B+8+=+424\"
\n" ); document.write( "\"4x+=+416\"
\n" ); document.write( "\"x+=+104\"\r
\n" ); document.write( "\n" ); document.write( "So, the other length is 108.\r
\n" ); document.write( "\n" ); document.write( "Check... 104+108+104+108 is 424. Therefore, a correct answer :-)\r
\n" ); document.write( "\n" ); document.write( "cheers
\n" ); document.write( "Jon.
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