document.write( "Question 954462: A man invested in $4000, part at 5% and the remainder at 3% simple interest. The total income is $168. How much does he invest at each Rate? \n" ); document.write( "
Algebra.Com's Answer #582925 by macston(5194)![]() ![]() You can put this solution on YOUR website! F=amount at 5%; T=amount at 3% \n" ); document.write( "F+T=$4000 \n" ); document.write( "T=$4000-F \n" ); document.write( "0.05F+0.03T=$168 Substitute for T. \n" ); document.write( "0.05F+0.03($4000-F)=$168 \n" ); document.write( "0.05F+$120-0.03F=$168 Subtract $120 from each side. \n" ); document.write( "0.02F=$48 \n" ); document.write( "F=$2400 ANSWER 1: He invests $2400 at 5%. \n" ); document.write( "T=$4000-F=$4000-$2400=$1600 ANSWER 2: He invested $1600 at 3%. \n" ); document.write( "CHECK: \n" ); document.write( "0.05F+0.03T=$168 \n" ); document.write( "0.05($2400)+0.03($1600)=$168 \n" ); document.write( "$120+$48=$168 \n" ); document.write( "$168=$168 \n" ); document.write( " |