document.write( "Question 954447: Perimeter of rectangular field is 3/5 km and it's length is twice its breadth. Find the of field in m.\r
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Algebra.Com's Answer #582920 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "Perimeter of rectangular field is \"P=2L%2B2W\"\r
\n" ); document.write( "\n" ); document.write( "if \"P=%283%2F5%29km\" and it's length is twice its breadth, \"L=2W\", then we have\r
\n" ); document.write( "\n" ); document.write( "\"%283%2F5%29km=2%2A2W%2B2W\"..............convert \"%283%2F5%29km\" in meters and solve for \"W\"\r
\n" ); document.write( "\n" ); document.write( "\"%283%2F5%29km=%283%2F5%291000m=%283000%2F5%29m=600m\"
\n" ); document.write( "\"600m=4W%2B2W\"
\n" ); document.write( "\"600m=6W\"
\n" ); document.write( "\"600m%2F6=W\"
\n" ); document.write( "\"W=100m\"\r
\n" ); document.write( "\n" ); document.write( "find the length:\r
\n" ); document.write( "\n" ); document.write( "\"L=2W\"
\n" ); document.write( "\"L=2%2A100m\"
\n" ); document.write( "\"L=200m\"\r
\n" ); document.write( "\n" ); document.write( "so, dimensions of the field: \"200m\" by \"100m\"\r
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