document.write( "Question 954431: ray packerd starts out on a boating trip at 8am. rays boat can go 20 mph in still water. how far downstream can ray go if the current is 5 mph and he wishes to go down and back in 4 hours? \n" ); document.write( "
Algebra.Com's Answer #582901 by macston(5194)\"\" \"About 
You can put this solution on YOUR website!
d=distance
\n" ); document.write( "\"d%2F%2820mph%2B5mph%29%2Bd%2F%2820mph-5mph%29=4hrs\"
\n" ); document.write( "\"d%2F25mph%2Bd%2F15mph=4hrs\"
\n" ); document.write( "\"d%281%2F25mph%2B1%2F15mph%29=4hrs\"
\n" ); document.write( "\"d%283%2F75mph%2B5%2F75mh%29=4hrs\"
\n" ); document.write( "\"d%288%2F75mph%29=4hrs\"
\n" ); document.write( "\"d=4hrs%2875mph%2F8%29\"=\"%28300%2F8%29miles=37.5miles\" ANSWER: Ray could go 37.5 miles.
\n" ); document.write( "CHECK:
\n" ); document.write( "\"37.5mi%2F25mph%2B37.5mi%2F15mph=4hrs\"
\n" ); document.write( "\"1.5hrs%2B2.5hrs=4hrs\"
\n" ); document.write( "\"4hrs=4hrs\"
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