document.write( "Question 954398: A rectangle has a length that is five times longer than its width. If the perimeter of the rectangle is 12 inches, what is the width?\r
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\n" ); document.write( "\n" ); document.write( "I got the equation 5w+w=12 and with that i added 5w+w and got 6w=12... After that i divided 6w and got 2... That was the wrong answer... My teacher said it was one and didnt explain how to get that answer... I am just confused... If you could help me it would be extremely appreciated..
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Algebra.Com's Answer #582894 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "given:
\n" ); document.write( "a rectangle with a length \"L\" and a width \"W\"
\n" ); document.write( "given that a rectangle has a length \"L\" that is five times longer than its width \"W\"
\n" ); document.write( "=> \"L=5W\"\r
\n" ); document.write( "\n" ); document.write( "given that the perimeter of the rectangle is \"P=12in\", and you know that \"P=2L%2B2W\"
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\n" ); document.write( "so,\"2L%2B2W=12in\"\r
\n" ); document.write( "\n" ); document.write( "since given that \"L=5W\",substitute it in \"2L%2B2W=12in\"\r
\n" ); document.write( "\n" ); document.write( "\"2%2A5W%2B2W=12in\"...........solve for \"W\"\r
\n" ); document.write( "\n" ); document.write( "\"10W%2B2W=12in\"\r
\n" ); document.write( "\n" ); document.write( "\"12W=12in\"\r
\n" ); document.write( "\n" ); document.write( "\"W=12in%2F12\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28W=1in%29\"\r
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\n" ); document.write( "\n" ); document.write( "so,the width is \"highlight%281in%29\"\r
\n" ); document.write( "\n" ); document.write( "then the length is \"highlight%285in%29\"\r
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\n" ); document.write( "\n" ); document.write( "check perimeter:\r
\n" ); document.write( "\n" ); document.write( "\"P=2%2A5in%2B2%2A1in\"\r
\n" ); document.write( "\n" ); document.write( "\"P=10in%2B2in\"\r
\n" ); document.write( "\n" ); document.write( "\"P=12in\"
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