document.write( "Question 954398: A rectangle has a length that is five times longer than its width. If the perimeter of the rectangle is 12 inches, what is the width?\r
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\n" ); document.write( "\n" ); document.write( "I got the equation 5w+w=12 and with that i added 5w+w and got 6w=12... After that i divided 6w and got 2... That was the wrong answer... My teacher said it was one and didnt explain how to get that answer... I am just confused... If you could help me it would be extremely appreciated..
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Algebra.Com's Answer #582883 by Alan3354(69443)\"\" \"About 
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A rectangle has a length that is five times longer than its width. If the perimeter of the rectangle is 12 inches, what is the width?
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\n" ); document.write( "I got the equation 5w+w=12 and with that i added 5w+w and got 6w=12... After that i divided 6w and got 2... That was the wrong answer... My teacher said it was one and didnt explain how to get that answer... I am just confused... If you could help me it would be extremely appreciated..
\n" ); document.write( "Perimeter = 2W + 2L = 12
\n" ); document.write( "W + L = 6, not 12 --> your calculations would be 1.
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\n" ); document.write( "But, 5 times longer is not 5 times as long, it's 6 times.
\n" ); document.write( "W + 6W = 6
\n" ); document.write( "W = 6/7 inches
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\n" ); document.write( "If 5 times longer = 5 times as long, what is 1 time longer? --> a 100% increase = 2 times as long.
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