document.write( "Question 954336: find the lateral area and surface area of a regular hexagonal pyramid with base edge length 4 meters and slant height 8 meters \n" ); document.write( "

Algebra.Com's Answer #582848 by macston(5194) $\"\"$ $\"About$

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b=base edge=4m; s=slant height=8m
\n" ); document.write( "lateral surface area=(6)(1/2)bs=3bs=3(4m)(8m)=96 sq m
\n" ); document.write( "ANSWER 1: The lateral surface area is 96 square meters.
\n" ); document.write( "Area of base:
\n" ); document.write( " $\"Area=%28%283sqrt%283%29%29%2F2%29b%5E2\"$ = $\"2.598%284%5E2m%5E2%29=2.598%2816m%5E2%29\"$ =41.57m
\n" ); document.write( "The area of the base is 41.57 square meters.
\n" ); document.write( "Surface area=lateral area + base area=96 sq m+41.57 sq m=137.57 sq m
\n" ); document.write( "ANSWER 2: The surface area is 137.57 square meters. \n" ); document.write( "

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