document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=952684>Question 952684</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangle has a length 9 meters longer than double the width. The perimeter is 210. Find the dimensions of the rectangle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #582845 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=582845\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> W=width; L=length=2W+9m; P=perimeter=2(L+W)=210m<BR>\n" );
document.write( "P=2(L+W)<BR>\n" );
document.write( "210m=2(L+W) Divide each side by 2.<BR>\n" );
document.write( "105m=L+W Substitute for L.<BR>\n" );
document.write( "105m=2W+9m+W Subtract 9m from each side.<BR>\n" );
document.write( "96m=3W Divide each side by 3.<BR>\n" );
document.write( "32m=W ANSWER 1: The width is 32 meters.<BR>\n" );
document.write( "L=2W+9m=2(32m)+9m=64m+9m=73m ANSWER 2: The length is 73 meters.<BR>\n" );
document.write( "CHECK:<BR>\n" );
document.write( "P=2(L+W)<BR>\n" );
document.write( "210 m=2(73 m+32 m)<BR>\n" );
document.write( "210 m=2(105 m)<BR>\n" );
document.write( "210 m=210 m </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );