document.write( "Question 954258: The sum of the digits of a two-digit number is 11. If the digits are reversed, the new number is 45 more than the original number. Find the number. Thankyou :))))))))) \n" ); document.write( "

Algebra.Com's Answer #582805 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let the tens digit = $\"+a+\"$
\n" ); document.write( "Let the units digit = $\"+b+\"$
\n" ); document.write( "-------------------------
\n" ); document.write( "(1) $\"+a+%2B+b+=+11+\"$
\n" ); document.write( "(2) $\"+10b+%2B+a+=+10a+%2B+b+%2B+45+\"$
\n" ); document.write( "------------------------------
\n" ); document.write( "(2) $\"+-9a+%2B+9b+=+45+\"$
\n" ); document.write( "(2) $\"+-a+%2B+b+=+5+\"$
\n" ); document.write( "-------------------
\n" ); document.write( "Add (1) and (2)
\n" ); document.write( " $\"+2b+=+16+\"$
\n" ); document.write( " $\"+b+=+8+\"$
\n" ); document.write( "and
\n" ); document.write( "(1) $\"+a+%2B+b+=+11+\"$
\n" ); document.write( "(1) $\"+a+=+11+-+b+\"$
\n" ); document.write( "(1) $\"+a+=+11+-+8+\"$
\n" ); document.write( "(1) $\"+a+=+3+\"$
\n" ); document.write( "---------------
\n" ); document.write( "The number is 38
\n" ); document.write( "--------------------
\n" ); document.write( "check:
\n" ); document.write( "With digits reversed: 83
\n" ); document.write( " $\"+83+-+38+=+45+\"$
\n" ); document.write( "83 is 45 more than 38
\n" ); document.write( "OK \n" ); document.write( "

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