document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=954145>Question 954145</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A truck can be rented from Company A for $110.00 a day plus $0.50 per mile. Company B charges $80.00 a day plus $0.80 per mile to rent the same truck. He many miles must be driven in a day to make the rental cost for Company A a better deal than company B? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #582757 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=582757\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> m=number of miles<BR>\n" );
document.write( "A=$110+$0.50m<BR>\n" );
document.write( "B=$80+$0.80m<BR>\n" );
document.write( "$110+$0.50m=$80+$0.80m Subtract ($80+$0.50m)<BR>\n" );
document.write( "$30=$0.30m Divide each side by $0.30<BR>\n" );
document.write( "100=m ANSWER: More than 100 miles must be driven per day to make Company A a better deal. </SPAN>\n" );
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