document.write( "Question 954196: The Howard family and the Gray family each used their sprinklers last summer. The water output rate for the Howard family's sprinkler was
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document.write( "40L per hour. The water output rate for the Gray family's sprinkler was
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document.write( "25L per hour. The families used their sprinklers for a combined total of
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document.write( "45 hours, resulting in a total water output of
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document.write( "1500L. How long was each sprinkler used?
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document.write( "Howards family sprinklers:___
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document.write( "Grays family sprinkler:___ \n" );
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Algebra.Com's Answer #582752 by macston(5194)![]() ![]() You can put this solution on YOUR website! H=Howards; G=Grays \n" ); document.write( "G+H=45 \n" ); document.write( "H=45-G \n" ); document.write( "40H+25G=1500 Substitute for H \n" ); document.write( "40(45-G)+25G=1500 \n" ); document.write( "1800-40G+25G=1500 Subtract 1800 from each side, \n" ); document.write( "-15G=-300 Divide each side by -15 \n" ); document.write( "G=20 ANSWER 1: The Grays sprinkler was used 20 hours. \n" ); document.write( "H=45-G=45-20=25 ANSWER 2: The Howards sprinkler was used 25 hours. \n" ); document.write( "CHECK: \n" ); document.write( "40H+25G=1500 \n" ); document.write( "40(25)+25(29)=1500 \n" ); document.write( "1000+500=1500 \n" ); document.write( "1500=1500\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |