document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=954181>Question 954181</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Larry Mitchell invested part of his 22,000 advance at 4% annual simple interest and the rest at annual simple interest. If his total yearly interest from both accounts was 810, find the amount invested at each rate. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #582734 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=582734\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Not enough info given: we know the second account pays less than the first, so let's use 2% as an example<BR>\n" );
document.write( "F=amount at 4%; T=amount at 2%<BR>\n" );
document.write( "F+T=22000<BR>\n" );
document.write( "T=22000-F<BR>\n" );
document.write( "0.04F+0.02T=810 Substitute for T<BR>\n" );
document.write( "0.04F+0.02(22000-F)=810<BR>\n" );
document.write( "0.04F+440-0.02F=810 Subtract 440 from each side.<BR>\n" );
document.write( "0.02F=370 Divide each side by 0.02<BR>\n" );
document.write( "F=18500 ANSWER 1: 18500 was invested at 4%.<BR>\n" );
document.write( "T=22000-18500=3500 ANSWER 2: 3500 was invested at 2%.<BR>\n" );
document.write( "CHECK:<BR>\n" );
document.write( "0.04F+0.02T=810<BR>\n" );
document.write( "0.04(18500)+0.02(3500)=810<BR>\n" );
document.write( "740+70=810<BR>\n" );
document.write( "810=810<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );