document.write( "Question 954123: 1.on earth the acceleration g. due to gravity is approximately 32ft/second. using the formula v=√2gd ,what is the velocity of an object after falling 7ft from the point where it was dropped?\r
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Algebra.Com's Answer #582710 by macston(5194)\"\" \"About 
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g=32ft/sec^2; \"d=7ft\"; \"v=velocity\"=\"sqrt%282gd%29\"; \"s%5E2=seconds%5E2\"
\n" ); document.write( "\"v=sqrt%282gd%29\"
\n" ); document.write( "\"v=sqrt%282%2832ft%2Fseconds%5E2%29%287ft%29%29\"
\n" ); document.write( "\"v=sqrt%282%28224ft%5E2%2Fseconds%5E2%29%29\"
\n" ); document.write( "\"v=sqrt%28448ft%5E2%2Fseconds%5E2%29\"=21.2 ft/sec
\n" ); document.write( "ANSWER: The objects velocity 7 seconds after being dropped is 21.2 ft/sec.
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