document.write( "Question 954012: An aeroplane flies from A to B at a speed of 750km/h. On the returnn trip there was a strong tail wind and airplane flew at 900km/h. The return trip took 20min less than original. How many hours did the return trip take? \n" ); document.write( "

Algebra.Com's Answer #582689 by hemu_da(13) $\"\"$ $\"About$

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Suppose t is the normal time to travel from A to B. \r
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\n" ); document.write( "\n" ); document.write( "Speed on return trip is 900 km/hr.\r
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\n" ); document.write( "Time taken is 20 min less than the original ( which is t here). \r
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\n" ); document.write( "I.e. $\"t-%2820%2F60%29+=+t-%281%2F3%29\"$ hr\r
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\n" ); document.write( "In both the trip distance is same that is...\r
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\n" ); document.write( " $\"750%2At+=+900%2A%28t-%281%2F3%29%29\"$
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\n" ); document.write( "5t = 6t - 2
\n" ); document.write( "t = 2 hr.
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\n" ); document.write( "Returning trip take 20 min less than the original, hence time is-- \r
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\n" ); document.write( " 2 hr - 20 min = 1 hr 40 min.\r
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