document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=954079>Question 954079</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sharp razor company manufactures two types of electric shavers. one shaver is cordless and requires 5 hours to make. the other shaver has an electric cord and takes 3 hours to make. the company has only 16 work hours per day to manufacture shavers. the despatch department can pack and ship at most 300 shavers per day. let x be the number of cordless shavers made per day and y be the number of shavers with a cord manufactured per day. what is the correct system of linear equations that represent this situation?? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #582682 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=582682\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x+y= 300 therefore x= 300-y<BR>\n" );
document.write( "5x+3y=16 <BR>\n" );
document.write( "We can substitute in the first equation:<BR>\n" );
document.write( "300-y+y= 16<BR>\n" );
document.write( "300= 16 and this is what the problem says, they can pack at most 300 and they work 16 hours. </SPAN>\n" );
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