document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=954072>Question 954072</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Max,Mon and Mitch are cousins and the sum of their ages is 64. Find their ages if Max is 3 times as old as Mitch and Mon's age is 4 more than twice the age of Mitch. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #582681 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=582681\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Ma+Mo+Mi = 64<BR>\n" );
document.write( "Ma= Mi x 3<BR>\n" );
document.write( "Mo= 2Mi+4 Substituting in the 1st formula:<BR>\n" );
document.write( "(Mix3)+2Mi+4+Mi= 64 Subtract 4 from both sides and add the Mi on left:<BR>\n" );
document.write( "Mix3+3Mi= 60 To make it easier, we break down the multiplication:<BR>\n" );
document.write( "Mi+Mi+Mi+3Mi= 60<BR>\n" );
document.write( "6Mi= 60<BR>\n" );
document.write( "Mi= 10<BR>\n" );
document.write( "Answer:<BR>\n" );
document.write( "Mi is 10<BR>\n" );
document.write( "Ma is 10x3= 30<BR>\n" );
document.write( "Mo is 2(10)+4= 24<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "10+30+24= 64 We've got the correct answer.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );