document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=954031>Question 954031</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If x - y = -15 and I have the numbers on the table the thing I have a problem with is getting y by itself like my math teacher told me to (Pre Algebra) could you like explain to me how to get y by itself so I can find the y by doing the stuff to x<BR>\n" );
document.write( "x-y<BR>\n" );
document.write( "2,y<BR>\n" );
document.write( "1,y<BR>\n" );
document.write( "0,y<BR>\n" );
document.write( "-1,y </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #582648 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=582648\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You might try putting everything on one side:<BR>\n" );
document.write( "x-y=-15 Add 15 to each side.<BR>\n" );
document.write( "x-y+15=0 Now just cancel the y on the non-zero side, it winds up alone on the other side. Add y to each side.<BR>\n" );
document.write( "x+15=y <BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );