document.write( "Question 954010: Solve algebraically for x: log5x-1 4=1/3 \n" ); document.write( "
Algebra.Com's Answer #582642 by MathTherapy(10552)\"\" \"About 
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Solve algebraically for x: log5x-1 4=1/3
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document.write( "If \"log+%285x+-+1%2C+4%29+=+1%2F3\", then:
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document.write( "\"log+%285x+-+1%2C+4%29+=+1%2F3\" ---------- Logarithmic form
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document.write( "\"highlight%28highlight%28%285x+-+1%29%5E%281%2F3%29+=+4%29%29\" --------- Exponential form
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document.write( "\"highlight%28highlight%28%285x+-+1%29%5E%28%281%2F3%29+%2A+3%29+=+4%5E3%29%29\" ---- Cubing both sides
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document.write( "5x – 1 = 64
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document.write( "5x = 64 + 1
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document.write( "5x = 65
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document.write( "x = \"65%2F5\", or \"highlight_green%2813%29\" \n" );
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