document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=954009>Question 954009</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Carl rode his bike to the city at a rate of 10 miles per hour and returned immediately on a bus traveling the same route at a rate of 50 miles per hour. If the entire trip took 6 hours, how far is Car's house from the city? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #582636 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=582636\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> s=distance from city<BR>\n" );
document.write( "s/10mph+s/50mph=6 hours<BR>\n" );
document.write( "5s/50mph+s/50mph=6 hrs<BR>\n" );
document.write( "6s/50mph=6hrs<BR>\n" );
document.write( "6s=6hrs(50mph)=300 mi<BR>\n" );
document.write( "s=50 mi ANSWER: Carl's house was 50 miles from the city.<BR>\n" );
document.write( "CHECK:<BR>\n" );
document.write( "50 mi/10mph+50mi/50mph=6 hours<BR>\n" );
document.write( "5 hours + 1 hour=6 hours<BR>\n" );
document.write( "6 hours=6hours </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );