document.write( "Question 953994: Dean's and April's ages have a sum of 55 years.
\n" ); document.write( "In two years Dean will ne twice as old as April was 12 years ago. Find their present ages
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Algebra.Com's Answer #582621 by lwsshak3(11628)\"\" \"About 
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Dean's and April's ages have a sum of 55 years.
\n" ); document.write( "In two years Dean will be twice as old as April was 12 years ago. Find their present ages
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\n" ); document.write( "let x=Dean's age
\n" ); document.write( "55-x=April's age
\n" ); document.write( "..
\n" ); document.write( "12 yrs ago:
\n" ); document.write( "55-x-12=43-x=April's age
\n" ); document.write( "..
\n" ); document.write( "In 2 yrs:
\n" ); document.write( "x+2=2(43-x)
\n" ); document.write( "x+2=86-2x
\n" ); document.write( "3x=84
\n" ); document.write( "x=28
\n" ); document.write( "55-x=27
\n" ); document.write( "Dean's age=28
\n" ); document.write( "April's age=27
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