document.write( "Question 953994: Dean's and April's ages have a sum of 55 years.
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document.write( "In two years Dean will ne twice as old as April was 12 years ago. Find their present ages
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Algebra.Com's Answer #582621 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Dean's and April's ages have a sum of 55 years. \n" ); document.write( "In two years Dean will be twice as old as April was 12 years ago. Find their present ages \n" ); document.write( "*** \n" ); document.write( "let x=Dean's age \n" ); document.write( "55-x=April's age \n" ); document.write( ".. \n" ); document.write( "12 yrs ago: \n" ); document.write( "55-x-12=43-x=April's age \n" ); document.write( ".. \n" ); document.write( "In 2 yrs: \n" ); document.write( "x+2=2(43-x) \n" ); document.write( "x+2=86-2x \n" ); document.write( "3x=84 \n" ); document.write( "x=28 \n" ); document.write( "55-x=27 \n" ); document.write( "Dean's age=28 \n" ); document.write( "April's age=27 \n" ); document.write( " \n" ); document.write( " |