document.write( "Question 953995: Marion is five years younger than Susan
\n" ); document.write( "In 10 years susan will be three times as old as Marion was three years ago. Find their present ages
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Algebra.Com's Answer #582617 by lwsshak3(11628)\"\" \"About 
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Marion is five years younger than Susan
\n" ); document.write( "In 10 years susan will be three times as old as Marion was three years ago. Find their present ages
\n" ); document.write( "let x=
\n" ); document.write( "3 yrs ago:
\n" ); document.write( "x-5-3=x-8=Marian's age
\n" ); document.write( "In ten years:
\n" ); document.write( "x+10=Susan's age
\n" ); document.write( "x+10=3(x-8)
\n" ); document.write( "x+10=3x-24
\n" ); document.write( "2x=34
\n" ); document.write( "x=17
\n" ); document.write( "x-5=12
\n" ); document.write( "Susan's age=17
\n" ); document.write( "Marion's age=12
\n" ); document.write( "
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