document.write( "Question 953995: Marion is five years younger than Susan
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document.write( "In 10 years susan will be three times as old as Marion was three years ago. Find their present ages \n" );
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Algebra.Com's Answer #582617 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Marion is five years younger than Susan \n" ); document.write( "In 10 years susan will be three times as old as Marion was three years ago. Find their present ages \n" ); document.write( "let x= \n" ); document.write( "3 yrs ago: \n" ); document.write( "x-5-3=x-8=Marian's age \n" ); document.write( "In ten years: \n" ); document.write( "x+10=Susan's age \n" ); document.write( "x+10=3(x-8) \n" ); document.write( "x+10=3x-24 \n" ); document.write( "2x=34 \n" ); document.write( "x=17 \n" ); document.write( "x-5=12 \n" ); document.write( "Susan's age=17 \n" ); document.write( "Marion's age=12 \n" ); document.write( " |