document.write( "Question 953949: at the food store peanuts cost two dollars per pound and raisins cost four dollars per pound. Jillian bought a 7 pound mixture of peanuts and raisins for $20. how many pounds each of peanuts and raisins were in the mixture \n" ); document.write( "

Algebra.Com's Answer #582587 by josgarithmetic(39618) $\"\"$ $\"About$

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p peanuts
\n" ); document.write( "r raisins
\n" ); document.write( "7, pounds of the mixture;
\n" ); document.write( "r=7-p, raisins\r
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\n" ); document.write( "\n" ); document.write( " $\"%282%2Ap%2B4%2A%287-p%29%29=20\"$ , to account for cost, not price. The equation is all done for one variable.\r
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\n" ); document.write( "\n" ); document.write( "This problem CAN be done using two variables, and a lesson is available for such a solution method. The method was avoided here because the focus of the question did not include PRICE of the mixture, and because the \"p+r=7\" problem fact could be used early to form the key equation in one variable. \n" ); document.write( "

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