document.write( "Question 953904: Find k,given that 32,k,3; are consecutive terms of an arithmetic sequence \n" ); document.write( "

Algebra.Com's Answer #582584 by MathLover1(20850) $\"\"$ $\"About$

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Since the terms are in arithmetic sequence,the middle term is equal to average of first and the last term. \r
\n" ); document.write( "\n" ); document.write( "so, for $\"32\"$ , $\"k\"$ , $\"3\"$ the middle term $\"k=%2832%2B3%29%2F2=35%2F2\"$ or as decimal $\"k=17.5\"$ \r
\n" ); document.write( "\n" ); document.write( "or this way:\r
\n" ); document.write( "\n" ); document.write( "It's an arithmetic sequence so the difference between consecutive terms is constant.
\n" ); document.write( "the first difference is $\"32-k\"$ and the second difference is $\"k-3\"$ , so we have
\n" ); document.write( " $\"32-k+=k+-3\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"32%2B3+=2k+\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"35%2F2=k\"$
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