document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=953827>Question 953827</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given the points (2,6) and (-4,10) found on line AB; find the slope-intercept form of this line AB. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #582537 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=582537\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Given the points (2,6) and (-4,10) found on line AB; find the slope-intercept form of this line AB.<BR>\n" );
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document.write( "slope = (10-6)/(-4-2) = 4/-6 = -2/3<BR>\n" );
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document.write( "Form:: y = mx + b<BR>\n" );
document.write( "Solve for \"b\"::<BR>\n" );
document.write( "6 = (-2/3)2 + b<BR>\n" );
document.write( "6 = -4/3 + b<BR>\n" );
document.write( "b = 22/3<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "y = (-2/3)x + (22/3)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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document.write( " </SPAN>\n" );
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