document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=953811>Question 953811</A>: <I><SPAN STYLE=\"word-break: break-all;\"> one of the roots of 3x^2+p=5x ,is 2.Determine the value of p and the other root. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #582520 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=582520\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> one of the roots of 3x^2+p=5x ,is 2.Determine the value of p and the other root.<BR>\n" );
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document.write( "Using synthetic division::<BR>\n" );
document.write( "2)....3....-5....p<BR>\n" );
document.write( "......3.....1...|..p+2\r<BR>\n" );
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document.write( "p + 2 = 0<BR>\n" );
document.write( "p = -2<BR>\n" );
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document.write( "Quotient:: 3x+1<BR>\n" );
document.write( "Other root::<BR>\n" );
document.write( "3x+1 = 0<BR>\n" );
document.write( "x = -1/3<BR>\n" );
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document.write( "cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "------------- </SPAN>\n" );
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