document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=953760>Question 953760</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Joe and Nick are to share N54 such that Joe has N8 less than Nick. What are the shares of Joe and Nick? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #582494 by </B><A HREF=/tutors/aboutme.mpl?userid=Electoral><B>Electoral(2)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Electoral><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=582494\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 54N=Joe+Nick meaning they share half of 54. The problem also is saying Joe has 8 less (N-8) and that means Nick has to have a extra 8 (n+8)<BR>\n" );
document.write( "54(1/2)-8=27-8=19  Joe's share<BR>\n" );
document.write( "54(1/2)+8=27+8=35  Nick's share\r<BR>\n" );
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document.write( "Check answer 19N+35N=54N </SPAN>\n" );
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