document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=953739>Question 953739</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Suppose $1,500 is invested in an account at an annual interest rate of 8.5% compounded continously. how long will it take (to the nearest tenth of a year) will it take the investment to double in size? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #582486 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=582486\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Suppose $1,500 is invested in an account at an annual interest rate of 8.5% compounded continously. how long will it take (to the nearest tenth of a year) will it take the investment to double in size?<BR>\n" );
document.write( ".<BR>\n" );
document.write( "When you see \"compounded continuously\" think:<BR>\n" );
document.write( "A = Pe^(rt)<BR>\n" );
document.write( "if investment is \"doubled\" then A=2P:<BR>\n" );
document.write( "plug in what you know:<BR>\n" );
document.write( "2P = Pe^(.085t)<BR>\n" );
document.write( "2 = e^(.085t)<BR>\n" );
document.write( "ln(2) = .085t<BR>\n" );
document.write( "ln(2)/.085 = t<BR>\n" );
document.write( "8.2 years = t\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );