document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=953684>Question 953684</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A train leaves a station and travels east at 72km/h. Three hours later, a second train leaves on a parallel track and travels east at 120km/h. How much time will it take until the second train catches up to the first train? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #582442 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=582442\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A train leaves a station and travels east at 72km/h. Three hours later, a second train leaves on a parallel track and travels east at 120km/h. How much time will it take until the second train catches up to the first train?<BR>\n" );
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document.write( "let x=travel time of 2nd train<BR>\n" );
document.write( "x+3=travel time of 1st train<BR>\n" );
document.write( "distance=speed*travel time(same for both trains)<BR>\n" );
document.write( "72(x+3)=120x<BR>\n" );
document.write( "72x+216=120x<BR>\n" );
document.write( "48x=216<BR>\n" );
document.write( "x=4.5 <BR>\n" );
document.write( "How much time will it take until the second train catches up to the first train? 4.5 hrs </SPAN>\n" );
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