document.write( "Question 953653: Ernie has $3.35 in nickels and dimes. He has thirteen more nickels than dimes. How many of each coin does he have? \n" ); document.write( "
| Algebra.Com's Answer #582431 by macston(5194)     You can put this solution on YOUR website! n=nickels; d=dimes=n-13 \n" ); document.write( "$0.05n+$0.10d=$3.35 Substitute for d. \n" ); document.write( "$0.05n+$0.10(n-13)=$3.35 \n" ); document.write( "$0.05n+$0.10n-$1.30=$3.35 Add $1.30 to each side. \n" ); document.write( "$0.15n=$4.65 Divide each side by $0.15. \n" ); document.write( "n=31 ANSWER 1: There were 31 nickels. \n" ); document.write( "d=n-13=31-13=18 ANSWER 2: There were 18 dimes. \n" ); document.write( "CHECK \n" ); document.write( "$0.05n+$0.10d=$3.35 \n" ); document.write( "$0.05(31)+$0.10(18)=$3.35 \n" ); document.write( "$1.55+$1.80=$3.35 \n" ); document.write( "$3.35=$3.35 \n" ); document.write( " \n" ); document.write( " |