document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=953546>Question 953546</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if one custodian cleans a suite of offices in 3 hours. when a second worker is asked to join the regular custodian, the job takes only 1 1/2 hours. how long does it take the second worker to do the same job alone? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #582386 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=582386\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=amount  of time it takes the second worker working alone<BR>\n" );
document.write( "Second worker works at the rate of 1/x of the suite per hour<BR>\n" );
document.write( "Custodian works at the rate of 1/3 of the suite per hour<BR>\n" );
document.write( "Custodian and second worker together works at the rate of 1/(1.5)=2/3 of the suite per hour<BR>\n" );
document.write( "sooooo<BR>\n" );
document.write( "1/x + 1/3 = 2/3 multiply each term by  3x<BR>\n" );
document.write( "3+x=2x<BR>\n" );
document.write( "x=3 hours----time it takes second worker working alone<BR>\n" );
document.write( "Hope this helps----ptaylor </SPAN>\n" );
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