document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=81232>Question 81232</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please show me how to get the square root. Thanks \r<BR>\n" );
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document.write( "(5 square root of 6-4)(3square root of 6-1) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #58238 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=58238\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (5 square root of 6-4)(3square root of 6-1)<BR>\n" );
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document.write( "(5sqrt6 -4 )(3sqrt6 -1)<BR>\n" );
document.write( "Use FOIL to get this product:<BR>\n" );
document.write( "F: (5sqrt6*3sqrt6)= 15*6=90<BR>\n" );
document.write( "O: (5sqrt6 *-1) = -5sqrt6<BR>\n" );
document.write( "I: (-4*3sqrt6) = -4sqrt6<BR>\n" );
document.write( "L: -4*-1 =  4<BR>\n" );
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document.write( "Add the \"like\" terms to get<BR>\n" );
document.write( "= 94 - 9sqrt6<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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